Calculus Problem: Differentiation & Integration Question: If y = x 5 + 3x 2 , find the derivative dy/dx and the integral ∫ y dx . Solution: Given Function: y = x 5 + 3x 2 Step 1: Differentiation Differentiating with respect to x : dy/dx = (d/dx)(x 5 ) + (d/dx)(3x 2 ) Using the power rule (d/dx)(x n ) = nx n-1 : ∴ dy/dx = 5x 5-1 + 3(2x 2-1 ) = 5x 4 + 3(2x) Answer: dy/dx = 5x 4 + 6x Step 2: Integration Now, integrating with respect to x : ∫ y dx = ∫ (x 5 + 3x 2 ) dx Separating the terms: = ∫ x 5 dx + ∫ 3x 2 dx Using the integration rule ∫ x n dx = x n+1 / (n+1) : = x 5+1 / (5+1) + 3 · x 2+1 / (2+1) = x 6 /6 + 3 · x 3 /3 + C Here, the 3 cancels out. Answer: ∫ y dx = x 6 /6 + x 3 + C *(Where C is the constant of integration)*
Science MCQs
Empowering Minds Through Science & Math